How do I graph the Inverse of the function y=1/2^x-1+2

Answer 1

You calculate an inverse by solving for x in terms of y

y = 1/2^x-1 + 2

y - 2 = 1/2^x-1

log₂ (y - 2) = 1 - x

log₂ (y - 2) - 1 = -x

-log₂(y-2) + 1 = x

If you prefer,

-ln(y-2)/ln(2) + 1 = x, or

x = -ln(y-2)/ln(2) + 1

Changing into the inverse function, switch x and y

y = -ln(x-2)/ln(2) + 1