Raymond B. answered 03/17/21
Math, microeconomics or criminal justice
g(t) = height of the rocket at time t
domain should be from t=0 at liftoff until the time when it comes back and hits the ground
if it started at ground level, it hits the ground at twice the time it reaches max height
g'(t) = -32t + 80 = 0
t = 80/32 = 5/2 = 2 1/2 seconds
It hits the ground in 5 seconds. then the domain would be 0 to 5 or [0,5]
If it started at an unspecified height = h
g(t) = -16t^2 +80t + h = 0, solve for t, divide by -16t and complete the square
t^2 -5t = h/16
t^2 -5t + 25/4 = h/16 + 25/4 = (h+100)/16
t - 5/2 = + or - sqr(h+100)/16
t = 5/2 + or - (1/4)sqr(h+100)
t = 2 1/2 + or - (1/4)sqr(h+100)
domain then is [0, 2.5+(1/4)sqr(h+100]
that makes the domain interval larger than [0,5]