math question (algebra related, need assistance)

Question

The Navarro family bought 2 child and 2 adult movie tickets and paid $36.50. The Alfred family bought 5 child and 2 adult tickets and paid $60.50. How much does a child movie ticket cost?

Answer 1

2C+2A = 3650

5C +2A =6050

subtract 2nd from 1st equation

3C = 2400 divide by 3

C = $8.00 for child tickets

A = (3650-1600)/2 = 2050/2 = $10.25 for adult tickets

2(800) + 2(1025) = 1600+ 2050 = 3650

5(800)+ 2(1025) = 4000+2050 = 6050

Answer 2

2c + 2a = 36.50

5c + 2a = 60.50

Subtract top equation from bottom to eliminate a, then solve for c.