Bradford T. answered 03/15/21
Retired Engineer / Upper level math instructor
This is a Maclaurin series. Turns out that if you expand the Maclaurin series, only every 3rd term is non-zero.
f(x) = 6x2+24x5+72x8+ ...
Fitting the coefficients and exponents to a parabola and a line
∞
f(x) = ∑(15n2+3n+6)x3n+2 = 6x2+24x5+72x8+150x11+....
n=0
I plotted both the original function and the Maclaurin function and it is very accurate around zero.
Kelly H.
I have found the first few terms to be 0+({0}/{1!}*x)+({12}/{2!}*x^2)+({0}{3!}*x^3)... but I dont know how to convert it into summation notation03/15/21