evaluate g(-3), g(0),a nd g(4)

Question

Answer 1

OK, g(x) is a piecewise function, meaning it changes for different values of x as defined by the inequalities. So you need to find which inequality each value of x satisfies. I'll do the first one for you, x = -3. We have three inequalities:

x ≤ -1 (x is less than or equal to -1)

-1 < x < 2 (x is greater than -1 but less than 2)

x ≥ 2 (x is greater than or equal to 2)

-3 is less than -1, so the inequality that -3 satisfies is x ≤ -1. That means to use g(x) = -x + 4. Next, plug in x = -3:

g(x) = -x + 4

g(-3) = -(-3) + 4

g(-3) = 7

You try it for x = 0 and x = 4. Find which inequality is true for each value of x.

Answer 2

Since -3 is less than -1...

-(-3) + 4 = 3 + 4 = 7

The rest is on you.