Show that (3 over m+4 - 4 over m =6) can be written as 6m squared +25m +16=0?

Question

^{Am I supposed to solve for m? Even if so, how is that supposed to be done when you have m squared and m to deal with?}

^{Any assistance would be greatly appreciated.}

Answer 1

3/(m+4) - 4/m = 6

multiply by m(m+4) to get

3m -4(m+4) = 6m(m+4)

3m-4m -16 = 6m^2 + 24m

6m^2 +25m +16 = 0