Using the Table Values What is the X Value when f(x) is 3

Question

F(x) = x²-6x+8

Answer 1

F(x) = x²-6x+8

You didn't provide the Table, but it's asking what is the value of "x" when the function = 3.

So, we can equal the quadratic equation to 3 and find the value of x:

x² - 6x + 8 = 3

x² - 6x + 8 - 3 = 0

x² - 6x + 5 = 0

a = 1

b = -6

c = 5

Apply the Quadratic Formula to solve the quadratic equation:

x = (-b _± √b² - 4ac) / 2a

x = (-(-6) ± √(-6)² - 4 (1) (5)) / 2 (1)

x = (6 ± √36 - 20) / 2

x = (6 ± √16) / 2

x = (6 ± 4) / 2

x₁ = (6 + 4 ) / 2

x₁ = 5

x₂ = (6 - 4) / 2

x₂ = 1

The value of x when f(x) = 3 is:

x₁ = 5

x₂ = 1

Answer 2

You don't list the table values, but let's say x = 4.

4² - 6(4) + 8 = 3

16 - 24 + 8 = 3

-8 + 8 = 3

0 = 3

Well, that's not true, so 4 is not a value for x when f(x) = 3.

Answer 3

Table Values??

f(3)=-1