Anthony T. answered • 03/07/21
Patient Science Tutor
Take the derivative versus time after rearranging the equation to
V = C / 1.4P
dV/dt = C/1.4 dP-1/dt
dV/dt = - C/1.4P2 dP/dt
dV/dt = -1.4 x 360cc x 85 kPa / (1.4 x 3602 kPa2) x - 8kPa/min
dV/dt = 1.9 kPa/min
Anthony T.
Hi, it should be cc/min. I made a mistake in the unit.03/07/21
Lily E.
Hi, the 1.9 is still showing up as incorrect.03/07/21
Anthony T.
Maybe some other tutors can give their input.03/07/21
Anthony T.
I interpreted PV1.4=C to be 1.4PV =C. Is that correct?03/07/21
Lily E.
It's shown on my end as PV^1.4 = C.03/07/21
Anthony T.
Ah, I see the problem. I will try to rework it.03/07/21
Anthony T.
The equation to differentiate is V^1.4 = C/P. This gives 1.4 V^0.4 dV/dt = - C /P^2 dP/dt then dV/dt = -3.2 E^5/(P^2 x 1.4 x V^0.4) x -dP/dt = 24.2 cc/min. I hope this is right. I did it another way using natural logarithms and got the same answer.03/08/21
Lily E.
24.3 cc/min is right, thank you! :)03/08/21
Brenda D.
03/09/21
Lily E.
hello, the answer should be in cm^3/min. im not sure what 1.9 kPa/min would be in cm^3/min.03/07/21