The volume of a sphere is (4/3)pir^3 take the derivative of both sides
dV= (4/3)pi ( 3r^2) dr You are told dr=0.4 and you want dV when r=16
dV= 4pi(16)^2(.4)= 1687cm^3/min
Lily E.
asked 03/07/21A spherical snowball is melting in such a way that its radius is decreasing at rate of 0.4 cm/min. At what rate is the volume of the snowball decreasing when the radius is 16 cm.
(Note the answer is a positive number).
Please help!
The volume of a sphere is (4/3)pir^3 take the derivative of both sides
dV= (4/3)pi ( 3r^2) dr You are told dr=0.4 and you want dV when r=16
dV= 4pi(16)^2(.4)= 1687cm^3/min
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