cotx = cosx/sinx
sin2x = 2cosxsinx
cos2x = cos^2x - sin^2 = 1-sin^2x -sin^2x = 1-2sin^2x
cos2x + sin^2x = 1
cos2x = 1-sin^2x
1-cos2x = 1 - 1 + 2sin^2x = 2sin^2x
sin2x/(1-cos2x) = 2cosxsinx/2sin^2x = cosx/sinx = cotx
Jordan M.
asked 03/05/21Prove the following identity. Show all work.
cotx = cosx/sinx
sin2x = 2cosxsinx
cos2x = cos^2x - sin^2 = 1-sin^2x -sin^2x = 1-2sin^2x
cos2x + sin^2x = 1
cos2x = 1-sin^2x
1-cos2x = 1 - 1 + 2sin^2x = 2sin^2x
sin2x/(1-cos2x) = 2cosxsinx/2sin^2x = cosx/sinx = cotx
Mark M. answered 03/05/21
Mathematics Teacher - NCLB Highly Qualified
sin 2θ / (1 - cos 2θ)
(2 sin θ cos θ) / (1 - (1 - sin2 θ)
(2 sin θ cos θ) / sin2 θ
2 cos θ / sin θ
2 cot θ
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