chemistry question about PE & forward reaction cont.

Question

Given the following information about a forward reaction:

Heat of reactants is 100kJ

Heat of products is 20kJ

Heat of activated complex is 150 kJ

Activation energy for the uncatalyzed reaction is 50kJ

Heat of reaction (delta H) is -80kJ

What is the activation energy for the reverse reaction, in kJ?

What is the delta H of the reverse reaction, in kJ?

Answer 1

Ea for reverse reaction is 150 - 20 = 130 kJ

∆H for reverse reaction is 100 - 20 = +80 kJ

This is a lot easier to see if you draw the energy graph, which I cannot do on this platform.