Ellie55 V.
asked 03/01/21Genetic code exercise
an mRNA segment encodes the peptide Met- Thr - Phe - Ile - Trp. Proflavin causes the removal of a single base from the gene encoding this mRNA. The new peptide translated from the modified mRNA is Met-Pro-Ser-Tyr-Gly.
a) in which coding the base removal occurred
b) what is the order of normal mRNA bases?
c) what would be the amino acid sequence if a G were inserted after the first 3 bases of the mutated mRNA?
1 Expert Answer
The codon table is helpful for this, so you can find likely mRNA sequences.
We have Met-Thr-Phe-Ile-Trp. I'll make "X" as multiple possible bases.
Which could be: 5' AUG-ACX-UUX-AUX-UGG 3'
The new peptide is Met-Pro-Ser-Tyr-Gly, which could be:
5' AUG-CCX-UCX-UAX-GGX 3'
The differences start at the second codon, so I think the delete base is somewhere in there. I also don't see an A in position 4, so I'll check if base 4 is the missing base. We would then have:
5' AUG-CXU-UXA-UXU-GGX 3'
And it fits! So base 4 was removed.
Now we can use the mutant peptide to fill in the X's, just by seeing what overlaps.
5' AUG-ACC-UUC-AUA-UGG 3'
Now if G were inserted after the first 3 bases of the mutant mRNA, we'd get:
5' AUG-GCC-UUC-AUA-UGG 3'
And the resulting peptide is: Met-Ala-Phe-Ile-Trp
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Cory L.
this requires a lot of typing but i can help if you contact me04/01/21