3(x+1)^2+8=-16 Please help!

Question

it needs to be solved using the square root method

Answer 1

3(x+1)^2 +8 = -16

3(x+1)^2 = -24

(x+1)^2=-8

x+1 = + or - sqroot-8

x= -1 +sqroot-8 and -1- sqroot-8

you can simplify sqroot -8 to 2i sqroot2 if you like