A 20-inch TV set has a diagonal measuring 20 inches. What is the width and height of a 20 inch TV set if its width is 4 inches more than its height?

Answer 1

(H+4)^2 + H^2 = 20^2

2H^2 + 8H + 16 = 400

2H^2 + 8H - 384 = 0

H^2 + 4H - 192 = 0

H^2 + 4H + 4 = 196

(H+2)^2 = 196

H+2 = sqr196

H = -2 + 14

H = 12 inches in height

W = 16 inches wide

It's a 12-16-20 right triangle

or 3-4-5 triangle enlarged by factor of 4

9+16= 25