Math Problem x5

Question

The sum of the ages of Shane and Alexandra is 64 years. 11 years ago, Shane's age was 2 times Alexandra's age. How old is Shane now?

Answer 1

S+A = 64

S=64-A

S-11= 2(A-11) = 2A -22

S = 2A -11

S = -A +64

2S = -2A + 128

S = 2A -11

3S = 117

S = 117/3 = 39 years old for Shane now

A = 64 -39 = 25 years old for Alexandra now

39-11 = 2(25-11)

28 = 2(14)

Answer 2

S = Shane's Age

64 - S - Alexandra's Age

S - 11 = Shane's Age 11 years ago

64 - S - 11 = 53 - S = Alexandra's Age 11 years ago

Shane's age was twice Alexandra's age

S - 11 = 2(53 - S)

S - 11 = 106 - 2S

3S = 117

S = 39