Concentration of sulfuric acid and balanced equation

Question

Write the balanced neutralization reaction that occurs between H2SO4 and in KOH aqueous solution. Phases are optional.



Suppose 0.250 L of  0.500 M of H2SO4 is mixed with 0.200 L of  0.240 M KOH. What concentration of sulfuric acid remains after neutralization?

Answer 1

First, what is the balanced rxn?

H2SO4 + 2KOH ------> K2SO4 + 2H2O

Then, what are the mol quantities of the reactants? (V)(M) = #mol

(0.250 L)(0.500M) = 0.125 mol H2SO4

(0.200L)(0.240 M) = 0.048 mol KOH

0.048 mol KOH can only neutralize 0.024 mol H2SO4, from the balanced rxn above.

0.125 mol H2SO4 - 0.024 mol H2SO4 = 0.101 mol H2SO4 remaining

0.101 mol /(0.250 + 0.200L) = 0.224 M H2SO4 remains