Inactive Tutor answered 02/23/21
Tutor
New to Wyzant
y = sin[2π/3(x - 6)];
Period p = 2π/(2π/3) = 3.
Jordan M.
asked 02/23/21Determine the period of 𝑦 = sin 2π/3 ( 𝑥 − 6 )
Inactive Tutor answered 02/23/21
y = sin[2π/3(x - 6)];
Period p = 2π/(2π/3) = 3.
Inactive Tutor answered 02/23/21
Please see attached video for the quick graphical solution.
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