Yefim S. answered • 02/23/21

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V = π∫_{1}^{e}[2^{2} - (lnx + 1)^{2}]dx

Dryan H.

asked • 02/23/21

Set up, but do not evaluate, the integral which gives the volume when the region bounded by the curves y = Ln(x), y = 1, and x = 1 is revolved around the line y = -1.

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Yefim S. answered • 02/23/21

Tutor

5
(20)
Math Tutor with Experience

V = π∫_{1}^{e}[2^{2} - (lnx + 1)^{2}]dx

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