What is the equation of the line that passes through the point (−6,6) and has a slope of -5/3

Answer 1

Given the line passes through (-6,6) and the slope is -5/3, the equation of the line in point-slope form is:

y - 6 = -5/3 * (x + 6)

3y - 18 = -5(x + 6)

3y - 18 = -5x - 30

3y = -5x - 12

y = -5/3x -4

Answer 2

Here (x,y)=(-6,6) and m=-5/3

since y=mx+c

6=-5/3*(-6)+c

6=10+c

c=-4

this implies

y=-5/3x-4