A family of four members. The father is 2 years older than the mother. The sister is 2 years older than the brother. The sum of all the present ages is 64.

Question

A family of four members. The father is 2 years older than the mother. The sister is 2 years older than the brother. The sum of all the present ages is 64. Three years ago, the sum of their ages was 53. How old is each of them now? 

Answer 1

F=2+M

S=2+B

F+M+S + B = 64

2+M + M + 2+B + B = 64

2M + 2B = 60

M + B = 30

F+M +30 = 64

F+M = 34

2M +M = 34

3M = 34

M = 11 1/3, years old a little young for a mother

F = 13 1/3 years old, a little young for dad

F+M = 25

25+S +B = 64

S+B = 64-25 = 39

2+B + B = 37

2B = 37

B = 18 1/2 years old

S = 20 1/2 years old

3 years ago the age sum = 53

F-3 + M-3 + S-3 + B-3 = 53

F+M+S+B = 53+12 = 65 but that contradicts the given information that

F+M+S+B = 64, but close, just off by one, maybe a typo on the keyboard