Find the two consecutive integers whose product is 24 more than 3 times the first integer. What is the equation for this situation? What is the equation for this situation above?

Answer 1

n(n+1) = 3n + 24

n² - 2n - 24 =0

(n-6)(n+4)=0

n=6 and n+1=7 or

n=-4 and n+1=-3