A particular Algebra text has a total of 648 pages which is broken into two parts. The second part of the book has 162 more pages than the first part. How many pages are in each part of the book?

Question

A particular Algebra text has a total of 648 pages which is broken into two parts. The

second part of the book has 162 more pages than the first part. How many pages are in

each part of the book?

Answer 1

We can solve this problem by using a system of two equations:

We know there are 648 pages total so our first equation is:

1) 648 = A + B

We also know that the second part of the book has 162 more pages than the first:

2) A + 162 = B

By substituting A + 162 = B into the 1) equation we get:

648 = (A+162) + A --> 648 = 2A + 162 --> 486 = 2A --> A = 243 pages

A = 243

A + 162 = B --> B = 405

Therefore the first part of book has 243 pages and the second part has 405 pages.

Answer 2

Let x be the number of pages in the first part of the book. The Second Part has 162 more pages, so it has x + 162 pages. The two parts sum to 648 pages:

x + x + 162 = 648

Solve for x, the number of pages in the first part. The second part has x + 162 pages.

Answer 3

x+(x+162)=648

2x=486

x=243