How to solve it

Question

X/2+5y=12

3x+2y-40

Answer 1

Multiply the 1st equation by 6: 3x + 30y = 72

Subtract the 2nd equation: 28x=32

Divide by 28;: x =8/7

Answer 2

solution: 2(x/2+5y)=12*2 (multiply by 2 on both sides)

x+10y=24-eq1

3x+2y=40-eq2

now multiply equation1 by 3 so that in both of the equations x will have the same constant

3(x+10y)=24*3 3x+30y=72 -eq3

subtract eq1 from eq3 implies

28y=32

y=32/28=8/7

put the value of y in any one of the equation you get the value of x

3x+16/7=40

3x=40-16/7

3x=264/7

x=264/21=88/7