I need help. I have been trying to do this problem but I don’t get it.

Question

Find three consecutive odd integers such that four times the second integer is three less than the sum of the third integer and four times the first integer. Use variable n for the first integer.

An equation that models this problem is :___

The integers from least to greatest are ___, ___, and ___

Answer 1

The three consecuive odd integers:

n, n + 2, and n + 4

4(n + 2) = (n + 4) + 4n - 3

Can you solve for n and answer?