
Mike D. answered 02/19/21
Effective, patient, empathic, math and science tutor
Well suppose you produce x cases of soda and y of juice.
Then
x >= 0
y >= 0
Malt constraint : 2x + y <= 160
Sugar constraint : 3x + 4y <= 340
Profit = 30 (x+y).
So graphically.
On Desmos plot the feasible region, bounded by
x=0
y=0
2x+y = 160
3x+4y = 340
On your graph find the vertices of this region
At each vertex find (x,y) and calculate 30 (x+y)
Choose the vertex with the highest value of 30 (x+y)
That gives you the required number of cases