We simply substitute what's inside the parentheses for x.
f(2) = 2(2) - 6 = 4 - 6 = -2
2[g(b) + 1] = 2[b - 2b2 + 1] = 2b - 4b2 + 2
The rest are on you.
Lit G.
asked 02/18/211.f(2)
2. f (−12)
3. g(–1)
4. g (−13)
5. f(7) – 9
6. g(–3) + 13
7. f(h + 9) 15. g(3y)
8.2[g(b) + 1]
We simply substitute what's inside the parentheses for x.
f(2) = 2(2) - 6 = 4 - 6 = -2
2[g(b) + 1] = 2[b - 2b2 + 1] = 2b - 4b2 + 2
The rest are on you.
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