
Yuri O. answered 02/18/21
16 years online, 464 former SAT problems drilled down
x − 3y = 4 → equation (1)
2x + y = 1 → equation (2)
Multiply equation (2) by "3":
6x + 3y = 3 → equation (3)
Add equations (1) and (3):
x − 3y = 4
6x + 3y = 3
7x = 7 → solve to "x"
x = 1
Calculating "y" from equation (2):
y = 1 - 2x = 1 - 2 = -1