Math Alegbra 1 pre ap

Question

Write an equation in slope-intercept form for the line that passes through the points (6,-3) and (0,2)

Answer 1

First thing's first: They want us to write our linear equation in Slope-intercept form, so we will be writing the equation in the form of

y = mx + b

We are not given the slope, instead we have been given 2 points on the line.

We can calculate the slope using those two points and the slope formula [(y₂ - y₁)/(x₂ - x₁)]

Here are the two points we are given: (6,-3) and (0,2)

(2 - (-3)) ÷ (0 - 6) = 5 ÷ -6, so the slope is -5/6

NOTE: One of the 2 given points is our y-intercept - (0,2).

y = -5/6x + 2

Answer 2

m = slope = (2--3)/0-6) = 5/-6= -5/6

y=mx + b is the general linear equation in slope intercept form

y=-(5/6)x + b. Plug in either point to solve for b

2 = -(5/6)(0 + b

b = 2

y =-5x/6 + 2