What is the equation of the line that passes through the point (-6,3) and slope of -2/3?

Answer 1

y-3 = (-2/3)(x+6) in point slope form

y= (-2/3)x -1 in slope intercept form, with y intercept = -1

general form is y=mx+b where m=slope and b= intercept

3y-9 = -2x-12

2x+3y =-3 without fractions, integer coefficients