This is a system of equations problem. Here what you need to do is find the two equations and eliminate one of the two variables to determine the number.
"The sum of two numbers is 92" => S+L= 92 (using S for small and L for large for the purposes of the next part.
"three times the smaller number is subtracted from the larger number, the result is 12 = L-3S = 12
Now before you eliminate one of the variables, you'll need to multiply the second equation by -1 and rearrange is so the variables line up to eliminate the "L"
S + L = 92
3S - L = -12
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Using elimination you should get
4S =80
Therefore S=20. There's one of your two numbers. Now use this number to find the other number. We'll use the first one since that's easier:
20 + L = 92.
Therefore L = 72. There's your other number.
Check your answer however with the other equation, L-3S = 12!
72 - (3x20) = 12. Does it work? Looks good to me! :)
I hope this helps! If you're in need of additional assistance, please do not hesitate to reach out - I can tutor through video conference. Good luck!
