The given limit is of the form that is the limit definition of the derivative at a point: f ‘ (a) = limx→a(f(x)-f(a))/(x—a)
So, f(2) = 3 , f ‘ (2) = 4 and use the point (2,3) and the slope = 4 to write the tangent line equation in point-slope form.
Michael B.
asked 02/11/21Suppose that f(x) is a differentiable function. If lim x->2 (f(x)-3)/(x-2) = 4, find:
F(2)
f'(2)
The equation of the line through (2, f(2) ) tangent to the graph y = f(x)
The given limit is of the form that is the limit definition of the derivative at a point: f ‘ (a) = limx→a(f(x)-f(a))/(x—a)
So, f(2) = 3 , f ‘ (2) = 4 and use the point (2,3) and the slope = 4 to write the tangent line equation in point-slope form.
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