Algebra 1 Word Problem

Question

Sue and Lois live 13.5 km apart. At 10:00 AM each girl leaves her house and jogs toward the other. the ratio os Sue's speeed to Lois's speed is 5:4. If the girls meet at 11;15 AM, how fast does each jog?

Answer 1

Sophie,

I think I misread it first time. Sorry, I see you are looking for how fast each of them going. Speed is just distance divided by time, speed(Sue)=7.5km/1.25hour = 6kmh and 6km/1.25hour=4.8kmh

 

You will have the same ratio for the distance traveled because distance is directly proportional to speed.

d1 = distance covered by Sue

d2 = distance covered by Lois

d1=13.5(5/9)=7.5km

d1=13.5(4/9)=6km

When they started (10:00) and when they ended (11:15) are not necessary to calculate how much of the 13.5 km each covered. It's probably there to just throw you off.

I hope this helps.