We solve polynomial equations by making sure they are = 0, then factoring.
In this example, we can factor out x immediately (which will yield x= 0 as one of three solutions.
x (6x2 + 7x - 5) = 0
Now we can factor the remaining quadratic (a quick check of the discriminant, 169, reveals it is factorable):
x (2x - 1)(3x + 5) = 0. Finally, setting each factor = 0 and solving, gives ...
x=0 or x=1/2 or x=-5/3