y=64(0.13)^x
Let us take any value for x, and for simplicity, Take value of x equal zero,
at x=0
y = 64(0.13)^0
y= 64 * 1 =64 ,
when x start to increase, you can take the limt of y as x goes to ∞ .
limx → ∞ y = 64 (0.13)^∞ = 0 , hint : 0.13 = 13/ 100, when we raise to high power the
denominator start to rise faster than the numerator
and that's why the result goes to zero.
So, the graph will decay as x increase.
To calculate the rate of decrease you can take the derivative of y:
y = 64 (0.13)^x
y = 64 bx , where b = 0.13, d( bx )/dx = ln b* bx
dy /dx = 64( ln b) bx = 64 ( -2.0422) (0.13)^x = - 130.574 * (0.13)^x
the minus sign indicate that we have decreasing function.
Hannah C.
Thank you so much! This makes so much sense now!02/08/21