Irene R. answered 02/06/21
BS in Mechanical Engineering and Certified math teacher for 13 years
Hi Anthony,
You can solve this problem by creating two equations and solving them using elimination to find the number of tickets for each type.
Let's use the variable, s , to represent the NUMBER of student tickets and the variable, n , to represent the NUMBER of non-student tickets sold.
Since there was a total of 240 tickets sold, we can write the following equation to show this part of the situation: s + n = 240
Then using the ticket prices and the total amount of money taken in, we can write the following equation:
2s + 6n = 924
Now we can solve these two equations simultaneously using elimination:
s + n = 240
2s + 6 n = 924
Multiply the first equation by -2 and solve for n :
s + n = 240 becomes -2s + -2n = -480
2s + 6 n = 924 2s + 6n = 924
4n = 444
n = 111
Since there were 240 total tickets sold, s will be 129.
There were 111 non-student tickets and 129 student tickets sold.
Anthony S.
i love you so much thanks02/06/21