MATH PROMB VERY HARD!

Question

The admission fee at an amusement park is $4.00 for children and $5.80 for adults. On a certain day, 281 people entered the park, and the admission fees collected totaled 1313 dollars. How many children and how many adults were admitted?

Answer 1

Let c = number of children and a = number of adults.

4c + 5.8a = 1313

c + a = 281 --> c = 281-a

Substitute for c in the first equation

4(281-a) + 5.8a = 1313

1124 - 4a + 5.8a = 1313

1.8a = 189

a = 189/1.8 = 105

c = 281-105 = 176

176 children and 105 adults were admitted.