3log𝐵+2log𝐴−2log𝐵−2
Assuming we are condensing the log problem
3 log 𝐵 + 2 log 𝐴 − 2log 𝐵 − 2
Put the power back on logs
log 𝐵3 + log𝐴2 − log 𝐵2 − 2
addition turns into * and subtraction turns into ÷
log (B3/B2) + log A2- 2
log (b) + log A2- 2 (2 means log 102 with base 10)
log (b) + log A2- log 102
log (BA2/102)
log (BA2/100)