Find the slope-intercept form of an equation of the line ​perpendicular​ to the graph of ​y =-3x+ 5 ​and passing through (-3, 6).

Answer 1

equation of line in slope intercept form is y = mx + b, where m is slope and b is y intercept.

so slope of y=-3x + 5 is -3. Slope of perpendicular line is negative reciprocal or 1/3.

so equation of perpendicular line is y = x/3 + b, where b is y intercept

to find b, we use fact that line passes through (-3,6) and substitute -3 for x and 6 for y:

6 = -3/3 + b

7 = b

so equation is y = x/3 + 7