Chemistry Chapter 1 Review

Question

What is the final (Na+) when 35.0 mL of 0.150 M NaCl is mixed with 75.0mL of 0.050 M Na2SO4 and 20.0 mL of 0.100 M KCI? assume all compounds are completely soluble. Consider each compounds stoichiometry.

Please include the steps :)

Answer 1

Moles of Na⁺ from NaCl = 0.150M x 0.035L = 0.00525 moles

Mols of Na⁺ from Na₂SO₄ = 0.050M x 0.075L x 2 = 0.0075 moles (x2 bc there are 2 Na⁺ ions in Na₂SO₄)

Add moles and divide by total volume of all solutions

Concentration of Na⁺ = 0.01275 moles/ 0.13L = 0.098M