Mathcoach R. answered 02/04/21
Expert in Linear Algebra
Kyla,
an account that pays 6% annual interest, the principal grows in the following way
you multiply the principal by the factor 1.06 to get the next amount one year later:
now: Amount = Principal of $1200
after t=1year: Amount A_1= principal *(1.06) = 1272 = Principal + Interest (you multiply by the factor 1.06 to get the next amount one year later
New principal:1272
after t=2 years: A_2= 1272*(1.06) = or 1200*(1.06)^2 = 1348.32
New principal is 1348.32
after t=3 years: A_3 = 1348.32*(1.06) = or 1200(1.06)^3=1429.22
Using the coumpound interest formula: A=P(1+r/n)^(nt)
Set n=1 (compound once a year)--->nt = t
r=0.06
1+r = 1.06
Therefore after t=3 years, A =1200(1.06)^3 =1429.22