the length of a rectangle is 3 meters greater than 2 times the width.the perimeter of a rectangle is 30 meters.what is the length of the rectangle?

Answer 1

length L = 2w+3 where w is the width

w + 2w+3 + w + 2w+3 = 30

6w + 6 = 30

6w = 24

w=4

length is 2(4)+3 = 11

rectangle is 11 by 4

Answer 2

Lets say that w = width of the rectangle, to start. If the length of the rectangle is 3 meters greater than 2 times the width, the length of the rectangle is equal to 3 + 2w.

The perimeter of the rectangle is 2 * length of rectangle + 2 * width of the rectangle. With the perimeter being equal to 30 and width being w and length being 2w+3:

The perimeter of the rectangle is 2(w) + 2(2w+3) = 30.

We first need to find out w first, which will give us the width of the rectangle. Taking it step by step, we get:

1. 2w + 4w + 6 = 30
2. 6w + 6= 30
3. 6w = 24 which is done by subtracting both sides by 6 to put the variables on one side and the values on the other side
4. w = 4 which is done by dividing 6 on both sides

Ultimately, this gets width to be 4 meters. Now that we found the width, we need to plug w = 4 into the equation we set up for length which is 2w+3. That being said, the ANSWER is:

length of rectangle = 2(4)+3 = 11 meters