
Yuri O. answered 02/04/21
16 years online, 464 former SAT problems drilled down
m - number of meters under surface of water when intensity of light is 20%
1(1 - 0.04)m = 0.2
m = lg(0.2)/lg(0.96) ≅ 39.43 (m)
Jordan M.
asked 02/03/21The intensity of light decreases by 4% for each meter that it descends below the surface of the water. At what depth is the intensity of light only 20% of that at the surface?
Yuri O. answered 02/04/21
16 years online, 464 former SAT problems drilled down
m - number of meters under surface of water when intensity of light is 20%
1(1 - 0.04)m = 0.2
m = lg(0.2)/lg(0.96) ≅ 39.43 (m)
Tristin S. answered 02/04/21
Recent College Graduate Looking for Opportunities to Tutor Others
If we know that each meter the intensity of light decreases by 4 percent then that means the light 1 meter down is 96 percent as strong as the light above. So in this case, if we were x meters down, the intensity of the light would be 0.96x. In order to find the point at which the intensity is only 20 percent, we need to find the x value such that 0.96x = 0.20.
To solve this equation, we need to take log0.96 of both sides.
So, in this case, we get that x = log0.96(0.20). If your calculator allows you to input logs of any base, you're done. If it doesn't, you can do the alternative step listed below:
Alternatively, if you remember your log rules, x = log0.96(0.20) can be written as x = loga(0.20)/ loga(0.96) where a is any positive real number. So if we want to use ln (natural log, log base e), x could just as easily be written as ln(0.20)/ln(0.96).
In either case, the answer is approximately 39.43 meters.
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