Write a line in slope-intercept form that contains the point (8, -12) and is parallel to the line described by y = - 34x - 9.

Answer 1

Slope Intercept form of the equation of a line is written in the form "y = mx + b"

where m = the slope of the line and b = the y-intercept.

First thing that we know is the line is parallel to the line represented by this equation: y = -34x - 9.

If our line is parallel to this line, then their slopes must be the same, so the "m" in this equation just above is -34, which means that the "m" in the equation for our line will also be -34.

y = -34x + b

-12 = -34(8) + b

-12 = -272 + b

+ 272 +272

260 = b

b = 260, so our equation for our line is:

y = -34x + 260

Answer 2

Let's take a look at all the information we've been given.

We know the line contains point (8, -12) - which is written in (x,y) form.

We know the line is parallel to line y=-34x - 9, which means it has the same slope, -34.

Using the format y=mx + b, let's plug in what we know.

-12 = -34(8) + b

-12 = -272 + b

260 = b

So the final equation will be y = -34x + 260

To double check our work, we can plug in 8 for x, and make sure it comes out to -12.

y = -34(8) + 260

y = -12 (Correct!)