Trigonometric Functions

Question

Given that sec0=-9/4 and tan 0>0 find the value of the remaining trigonometric functions.

Find:

cos0=

Sin0=

Cot0=

Csc0=

Tan0=

Answer 1

sec0<0 and tan0>0 means quadrant III

cos0=-4/9, the inverse of secant

x^2 = 81-16 = 65, x =sqr65 = about 8

sin0 = -sqr65/9 = about -8/9

csc0 =-9/sqr65 = about -9/8

tan0 = sqr65/4 = about 2

cot0 = 4/sqr65 = about 1/2