find the discriminant of the following equation to determine the number and type of solutions it will have m^2 = 40m -400

Answer 1

m^2 -40m + 400 =0

b^2-4ac = 1600-4(1)(400) = 0

just one solution, a real number.

Or it's described as one solution that repeats twice.

graphically there is one x (or m) intercept, which is the vertex and minimum point of an upward opening parabola that just touches the x axis without crossing it, at the point (20,0).

m=40/2 + or - (1/2)sqr(0) = 20 + 0 and 20 -0 = 20 or 20. One solution repeated twice.

m=20