Please help-I am super stuck I will appreciate it.

Question

Write an equation in standard form of the line that passes through the given point and has the given slope m. Hint: put it in slope intercept form first.

(4, 3) m=7

Answer 1

The formula for determining the equation knowing the slope and one point on a straight line is

m = (y - y₁) / (x - x₁) where x₁ and y₁ are the coordinates of the line in question. In the present case, this would be 7 = (y - 3) / (x - 4) which can be rearranged to y = 7x -28 + 3.

The standard form for an equation in the first degree is ax + by = c.

So, in the present case, this is 7x - y = 25.

Answer 2

Hi Hassan! We know that slope intercept form is y=mx + b and given the information provided above, we can substitute these three values into the y=mx + b equation and see what is left over to solve for, and go from there.

So, we know that (4,3) is the same as (x,y) and m = 7, so put these into the y=mx + b equation and solve for b, since that's the only value we don't know yet. The equation would then look like this:

3 = 7(4) + b

3 = 21 + b

-18 = b

Once you solve for b, you get -18. Plug this value into the final equation for b and use 7 as the slope (m).

So, the final equation would be y = 7x -18. Standard form of this equation would be -7x + y = -18. Hope this helps! Feel free to reach out if you have any more questions or help needed.

Answer 3

Write an equation in standard form of the line that passes through the given point and has the given slope m. Hint: put it in slope intercept form first.

(4, 3) m=7

your slope intercept form is

y = mx + b now plug in your numbers.. m = 7, x = 4, y = 3 to find your b

If you get stuck from here, let me know i can help you with the next steps.