What is the equation of a parabola that intersects the x-axis at points (-1, 0) and (3, 0)?

Question

A. y=x^2+3x+2

B. y=x^2=2x-3

C. y=x^2+2x-3

D. y=x^2-3x+2

Answer 1

plug in (3,0). for A, (3)^2 + 3(3) +2 >0

for B (3)^2 -2(3)-3 = 0, assuming the 2nd = sign should be -

C and D dont' work.

plug (-1,0) into B. 0 = (-1)^2 -2(-1) -3 = 1+2-3 = 0 B works for both points

B is correct as y=x^2 -2x -3