y = 1/2x – 1
y = 4x + 6
You can solve a system of equations by graphing, elimination, substitution, or a combination of these methods.
Since each of these equations are in slope-intercept form, I would simply set them equal to each other; they each define y in a different way, but we can set the two y's equal to each other, since y is y.
1/2 x — 1 = 4x + 6
I'm going to multiply through by two to get rid of the fraction. You'll see that I simply doubled each term in the equation.
1x – 2 = 8x + 12
Now I will put the x's on one side of the equation and the integers on the other, by adding and subtracting.
1x – 2 = 8x + 12
–1x –12 –1x –12
–14 = 7x
Now I need to divide by 7 on each side so that I know what 1x equals.
–14 = 7x
___ ____
7 7
x = –2
We know what x is. We need to determine the value of y when x is –2. We can substitute this value of x in either of the two original equations.
y = 1/2x – 1 <one of original equations>
y = (1/2)(–2) – 1
y = (–2/2) – 1
y = (–1) – 1
y = –2
The two lines defined by the two original equations intersect at the point (–2 , –2). You were asked to check these values for x and y in the two original equations.
–2 =?= (1/2)(–2) – 1
–2 =?= (–2/2) – 1
– =?= –1 – 1
–2 = –2 One check confirmed. Now we need to check the second original equation.
–2 =?= (4)(–2) + 6
–2 =?= –8 + 6
–2 = –2 Second check confirmed. Point (–2 , –2) is on each line. It is the intersection point.