Find the 8th term of the geometric sequence whose common ratio is 3 / 2 and whose 1st term is 6

Answer 1

The geometric sequence has general term : k * (3/2)^(N-1)

The first term is then K=6 when N=1

So then f(N) = 6 * (3/2)^(N-1)

6, 9, 18, 27, 36, 45, 54, 63 are the first 8 terms

with N=1,2,3,4,5,6,7,8