
Bianca C. answered 01/23/21
Algebra and English Tutor
Hello Ashlyn!
I hope that this helps!
We are going to be using two expressions to describe this question. For variables, let's call the number of paint tubes 't' and number of paint brushes 'b'.
We are first going to make an expression to describe the prices of what was purchased.
A single Paint Tubes (t) costs $4.00
A single Paint brush (b) costs $0.50 .
The total amount spent was $20.
So,
4t+0.5b=20
But we still need to describe the amounts of everything that was purchased, so we have to make another equation...
2t=b
^This equation shows that the amount of paint brushes (b) purchased was double the amount of paint tubes (t) that were purchased. This was mentioned in the prompt.
So now we are left with these expressions:
4t+0.5b=20
2t=b
Now you must use some method to solve for this system of linear equations. I will just combine. b=2t. So, I will be plugging 2t into the top equation in b's place holder. *Because b is technically equal to 2t).
(b=2t)
So now...
4t + 0.5b =20
4t + 0.5(2t) = 20
becomes
4t + t = 20
Simplify
5t=20
Divide both sides by 5.
We are now left with t =4. So the amount of paint tubes purchased was 4. We now know what t is, so we can plug t=4 into either equation to find what b is. I will be using the second equation (b=2t):
b=2t
(t=4) so...
b= 2(4)
b=8.
So b = 8 and t =4.
Let's plug these values into the first equation to double check.
4t+0.5b=20
4(4) + 0.5(8)=20
16+4= 20.
These solutions would be correct.
So,
8 Paintbrushes and 4 paint tubes were purchased :)